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Author Topic: Danelectro true bypassing  (Read 18615 times)
DreamSeller
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« Reply #15 on: March 15, 2007, 12:57:07 AM »

I bent my french fries. Cant remember the exact things as it's not in front of me right now but I took a 22k resistor and hook it from ground to two different resistors. one was the resistor between the hi/low switch and the opamp mcdooby and the other was the resistor at the very top of the board between the switch and the pot.

I will post some sound samples at some stage but I get sounds kinda like a synth from one and glitchy sounds from the other and when I adjust the high low switch with the glitch I get a fuzzy distortion sound.

All wired up and in the same box, tight fit in these buggers. Unfortunatly I misjudged the hole so now there are two in the front but meh.
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DreamSeller
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« Reply #16 on: March 18, 2007, 02:31:49 AM »

Sound sample.

Recorded Guitar>Pedal>DI>Soundcard.

Clean>Normal Effect>Distortion Sound Bend>Normal Effect> Synth Sound Bend>Normal Effect> Distortion Sound Bend> Glitchy Sound Bend.

EDIT: Attachments not working, cant upload. Will try again later

-Dream
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Wild Zebra
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« Reply #17 on: April 04, 2007, 08:25:56 AM »

I have a blt i want to rehouse.  Commenting on the rainbow wires do any of the them carry the output signal?  I was hoping to just remove he switching board.   I would like to hook it up in a guitar.  With a dpdt. any suggestions.  I got the + and ground and quite possibly the input sig as you mentioned.  But will I most likely need to find the output on the effect board?
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expanoncolin
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« Reply #18 on: April 04, 2007, 04:04:53 PM »

Quote from: "Wild Zebra"
I have a blt i want to rehouse.  Commenting on the rainbow wires do any of the them carry the output signal?  I was hoping to just remove he switching board.   I would like to hook it up in a guitar.  With a dpdt. any suggestions.  I got the + and ground and quite possibly the input sig as you mentioned.  But will I most likely need to find the output on the effect board?

Which one are you doing?

I posted this some time ago on the diystompboxes forum, perhaps it will help:

Quote
After some searching it is fairly clear to me that there is some amount of confusion that ensues when someone asks about danelectro switching and the proper way to make it true bypass.

I have worked only with bypassing mini pedals, and all but the PB&J have used the same switching board (good move danelectro!).  The switching involves a bit plastic non-latching DPDT, but it is simply being used as an SPDT, which is used to trip a flip flop, which then switches a 4053... being used as a DPDT in this case, to bypass or unbypass the pedal.  The 4013 also provides a signal for the LED's on/off, as the LED is always on the other circuit board.  There are a variety of kludgy methods involving forcing the electronic switching into the non-bypassed state at all times, either by simply relying on the pedal to "turn on" as soon as power is applied, or by jumpering the switch, or by cutting some traces on the flip flop and hardwiring, so that the coontrol for the 4053 switching is always non-bypassed.  I tend to not like those methods... I always feel dirty using them, because you're leaving so much in tact that can be removed!  A whole circuit board, in fact.

Each dano mini (other than the PB&J) has 6 wires from the switching board to the effect board.  Not all of them are used all the time!  This is a sacrifice danelectro had to make when they decided to do one switching board.  The wires, in order starting with the one closest to the input jack, go (color may vary... but I haven't seen it do so)
Send (blue)
9V (green)
Ground (yellow)
No-bypass Send (orange)
Return (red)
LED control (brown)

No-bypass send is essentially a wire that always contains the input signal, regardless of whether the effect is bypassed or not.  It's used in some pedals (just the chicken salad as far as I know) and not in others.  If you look at the effect board and it is not connected to anything, you can just cut that wire.  LED control you can also ignore in any case, because you will be using your 3pdt for the LED on/off.  So that leaves you with a simple set of connections on the effect PCB to connect your 3pdt to... almost.  There one caveat is that on the switching board, all of these are biased to Vref...  (as far as I can tell-the last time I did a TB to a non-PB&J mini was very long ago... but I am about to do another and will report back).  So you will need to do the standard referencing...  100k to V+, 100k to ground, a cap with the negative end to ground and the positive to the junction of the resistors, the junction then connected to two 1meg resistors, each individually connected to .1uF caps, connected to the input and output... after the .1uF cap, you go to the switch.  Sort of a pain... I have not tried ignoring the bias but it might be possible.  It's up to you in the end whether it's easier or not to kludge the bypass.

For the PB&J, it's a bit different... you cannot remove the switching board because the switching is on the same board as the delay chip!  The three boards are switches, effect, and buffers.  There is no real way to get around using the buffer board.  The switches you can get rid of.  My current favorite way to do true bypassing, while retaining the ability to select long or short, is to cut legs 2 and 5 on the tiny SMD 4013, and then make a little jumper between legs 10 and 8.  Then, just do the TB to the jacks on the buffer board.  You can also simply use a DPDT for long/short...  take a look at the schem, you just ahve to cut a trace and switch a leg on the PT2395 between high and low, using the other throw of the switch for the LEDs.  The LED in the PB&J is a 3-leg two color LED, with a common anode (the center lug).  I just use the 3pdt to switch the center lug on and off, wiring two LEDs with their anodes connected and wired to that 3pdt switch's lug, and wiring the cathodes to the PCB.  Either way works dandy.  If you are really good, you'd make a new buffer board-the PB&J has a few very silly things, one of them being that the op amps are powered with 5v of headroom when 9v is available.

Good luck...


-Colin
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Wild Zebra
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« Reply #19 on: April 05, 2007, 07:18:43 AM »

It's the BLT slapback echo.  I also hear if you short pins 7 and 12 of the 4013 it's "always on"?  Then I could take out the jacks and use the ins and out respectively.  Correct?
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expanoncolin
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« Reply #20 on: April 05, 2007, 07:57:17 AM »

Quote from: "Wild Zebra"
It's the BLT slapback echo.  I also hear if you short pins 7 and 12 of the 4013 it's "always on"?  Then I could take out the jacks and use the ins and out respectively.  Correct?

That could be, I'm not sure because I don't have one in front of me but it sounds like it might work.  But why make your signal go through all of the nasty switching circuitry and buffers if you can just remove and entire PCB?

-Colin
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Wild Zebra
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« Reply #21 on: April 05, 2007, 09:08:45 AM »

Well I'd like to remove the entire PCB, but I'm a little confused.  I need to experiment a little tonight.  Let me give you what I think I know.

OK if I remove the whole pcb (switching)
Green is 9V
Yellow is Ground
Even with the board removed Orange (no bypass send) if it makes a connection on the "effect" PCB, this will be my input wire correct?

So how about output? Is it the return wire.  Or will this be a connection on the "effect" board I need to find.  I here this effect is similiar to the rebote delay so I can use that schem for starting reference.

And as you say in your post I may need to add extra circuitry
Quote
So you will need to do the standard referencing... 100k to V+, 100k to ground, a cap with the negative end to ground and the positive to the junction of the resistors, the junction then connected to two 1meg resistors, each individually connected to .1uF caps, connected to the input and output... after the .1uF cap, you go to the switch. Sort of a pain... I have not tried ignoring the bias but it might be possible. It's up to you in the end whether it's easier or not to kludge the bypass.
 or possibly will work with out (have to try without first)  Also I think I would understand the above circuitry in schematic form.

So how am I doing so far?
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expanoncolin
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« Reply #22 on: April 05, 2007, 10:26:41 AM »

Really it's very simple, I promise.  You can ignore the biasing part, with the extra circuitry, most likely.  I did and it was fine.  "send" is the input to the effect.  "return" is the output from the effect.  You don't need to look at the rebote delay schem at all.  You are only worrying about switching here, and it's really all layed out for you.

-Colin
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Wild Zebra
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« Reply #23 on: April 05, 2007, 11:51:24 AM »

Thanks I'll try that tonight.  And to be final when you say "send" you mean
the blue wire and not the no bypass send correct.  Thanks for the help and patience.  I will post results.
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expanoncolin
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« Reply #24 on: April 05, 2007, 02:04:19 PM »

Quote from: "Wild Zebra"
Thanks I'll try that tonight.  And to be final when you say "send" you mean
the blue wire and not the no bypass send correct.  Thanks for the help and patience.  I will post results.

Quote
No-bypass send is essentially a wire that always contains the input signal, regardless of whether the effect is bypassed or not. It's used in some pedals (just the chicken salad as far as I know) and not in others. If you look at the effect board and it is not connected to anything, you can just cut that wire.

Yes, I mean the other (blue) send.

-Colin
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Wild Zebra
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« Reply #25 on: April 06, 2007, 07:12:10 AM »

Well I fudged with it last night and never got it to work.  Tried that combo and many other variations.  I eventually killed the switching board.  So I'm really not sure if the effect board has been damaged.  So I gave up for now.  But I would like to press on.  One observation was at the battery connector I obviously had full battery power.  But at the rainbow wire connections on the effect board the presumed 9V measures half of the real power?
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expanoncolin
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« Reply #26 on: April 06, 2007, 10:17:02 AM »

Quote from: "Wild Zebra"
Well I fudged with it last night and never got it to work.  Tried that combo and many other variations.  I eventually killed the switching board.  So I'm really not sure if the effect board has been damaged.  So I gave up for now.  But I would like to press on.  One observation was at the battery connector I obviously had full battery power.  But at the rainbow wire connections on the effect board the presumed 9V measures half of the real power?

Do any of them have 9V?  Many should have 4.5V but not all of them.  Basically any holding a signal should have 4.5V.

-Colin
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Wild Zebra
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« Reply #27 on: April 06, 2007, 10:32:22 AM »

If I recall, no I don't remember any rainbow pin on the effect side to have 9V.  Oh and in addition to having all the colors mentioned I also had a brown wire.  On the end.  When plugging to the 9V green and brown was the only way the LED would like up.  No other wire with green did this.  Although this doesn't mean the whole circuit is getting power, right? just the led.
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expanoncolin
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« Reply #28 on: April 06, 2007, 11:04:09 AM »

Quote from: "Wild Zebra"
If I recall, no I don't remember any rainbow pin on the effect side to have 9V.  Oh and in addition to having all the colors mentioned I also had a brown wire.  On the end.  When plugging to the 9V green and brown was the only way the LED would like up.  No other wire with green did this.  Although this doesn't mean the whole circuit is getting power, right? just the led.

The post mentions the brown wire.  It's the LED control wire that turns the LED on and off.

-Colin
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Wild Zebra
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« Reply #29 on: April 06, 2007, 11:17:33 AM »

Well I guess that answers that part.  So were am I at.  Hooking up in the fashion I did doesn't work.  Have a advice for me in getting this thing off the ground?  

Quote
LED control (brown)
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